WeBWorK using host: https://webwork.pcc.edu, format: simple, seed: 658, course: orcca

$\newcommand{\substitute}[1]{{\color{blue}{{#1}}}}\newcommand{\amp}{&}$

Find the perimeter and area of the rectangle.

Use m for meters and m^2 for square meters.

Its perimeter is

and its area is

.

Solution

Using the perimeter and area formulas for a rectangle, we have:

$\begin{aligned} P\amp=2(\ell+w)\amp A\amp=\ell\cdot w\\ \amp=2(\substitute{14}+\substitute{5}) \amp \amp=\substitute{14}\cdot\substitute{5}\\ \amp=2(19)\amp\amp=70\\ \amp=38 \end{aligned}$

Since length and width were measured in meters, we find that the perimeter is $38$ meters and the area is $70$ square meters.