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Use the expression $\frac{5}{9}(F - 32)$ to evaluate some Celsius temperatures.

You may use degC for $^{\circ}\mathrm{C}\text{.}$

If a temperature is $50{^\circ}\mathrm{F}$ what is that temperature measured in Celsius?

If a temperature is $-20{^\circ}\mathrm{F}$ what is that temperature measured in Celsius?

Solution

$\begin{aligned}[t] \frac{5}{9}(F - 32)\amp=\frac{5}{9}(\substitute{50} - 32)\\ \amp=\frac{5}{9}(18)\\ \amp=\frac{5}{1}(2)\\ \amp=10 \end{aligned}$
So $50{^\circ}\mathrm{F}$ is equavalent to $10{^\circ}\mathrm{C}\text{.}$

$\begin{aligned}[t] \frac{5}{9}(F - 32)\amp=\frac{5}{9}(\substitute{-20} - 32)\\ \amp=\frac{5}{9}(-52)\\ \amp=-\frac{260}{9}\\ \amp\approx-28.89 \end{aligned}$
So $-20{^\circ}\mathrm{F}$ is equavalent to about $-28.89{^\circ}\mathrm{C}\text{.}$

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