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Evaluate ${\left(-y\right)^{2}}$ when $y=-2$ .

Evaluate ${\left(-y\right)^{3}}$ when $y=-2$ .

Solution

$\displaystyle{\begin{aligned}[t] {\left(-y\right)^{2}} &= \big( -1(-2) \big)^2 \\ &= ( 2 )^2 \\ &= {4} \end{aligned}}$

$\displaystyle{\begin{aligned}[t] {\left(-y\right)^{3}} &= \big( -1(-2) \big)^3 \\ &= ( 2 )^3 \\ &= {8} \end{aligned}}$

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