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$\sqrt{\dfrac{1}{25}}=$

$\sqrt{\dfrac{4}{9}}=$

$\sqrt{\dfrac{81}{121}}=$

Solution

Since $\sqrt{1}=1$ and $\sqrt{25}=5\text{,}$ then $\sqrt{\dfrac{1}{25}}=\dfrac{1}{5}\text{.}$

Since $\sqrt{4}=2$ and $\sqrt{9}=3\text{,}$ then $\sqrt{\dfrac{4}{9}}=\dfrac{2}{3}\text{.}$

Since $\sqrt{81}=9$ and $\sqrt{121}=11\text{,}$ then $\sqrt{\dfrac{81}{121}}=\dfrac{9}{11}\text{.}$

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