To clear fractions in an equation, we multiply each term by a common denominator. For this problem, a common denominator is $6$. $$\begin{aligned} 5 &= \frac{t}{3}+ \frac{t}{2} \\ 6 \cdot 5 &= 6 \cdot \frac{t}{3}+ 6 \cdot \frac{t}{2} \\ 30 &= 2t + 3t \\ 30 &= 5t \\ \frac{30}{5} &= \frac{5t}{5} \\ 6 &= t\\ t & = 6 \end{aligned}$$ The solution to this equation is $6$. To stress that this is a value assigned to $t$, some report $t = 6$. We can also say that the solution set is $\{6\}$, or that $t\in\left\{6\right\}$. If we substitute $6$ in for $t$ in the original equation $5=\frac{t}{3}+\frac{t}{2}$, the equation will be true. Please check this on your own; it is an important habit.