$x$ $f(x)$ $g(x)$ $-4$ $3$ $4$ $-3$ $-4$ $-3$ $-2$ $4$ $2$ $-1$ $4$ $-3$ $0$ $-1$ $-3$
Use the table defining $f$ and $g$ to solve:
NOTE: Write Does not exist if the value does not exist.

a) $(f - g)(-4) =$

b) $(f + g)(-4) - (g-f)(-1) =$

c) $\displaystyle \left(\frac{f}{g}\right)(-4) =$